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C++ library that uses charAt()?

Hey, can somebody tell me if C++ has a function called charAt() in any of it's libraries? I'm using Visual Studio.NET Professional 2003 if that helps.

If it doesn't, can somebody give me a rough guideline as to how do program the function myself, or even just give me it?

doesnt charAt just loop till it finds index? if so, why not something like this?

Code:

char charAt(char *somestring,int count) {
int i;
for (i = 0; i < count; i++) {
somestring++;
}

return *somestring;
}

without any checking to make sure it won't fail, its actually easier than that. pos is the offset into the string, 0 will return first character.

Code:

char charAt(char *str, int pos)
{
return(str[pos]);
}

___________________

--Life would make more sense if I had the source code--

wow, that is possible, such a simple thing yet i never picked up on that...

Hey, thanks the principle behind that worked.

Incidentally, when I did that it didn't really work, it gave me errors about converting string to char which I half expected, but even just:

#include<iostream>
#include<string>

using namespace std;

int main()
{
string name;
name="abcdefg";
cout << name[3];
return 0;
}

hopefully returns "d".

I just didn't realise that a string was an array of characters that you could access easily, so it's pretty easy to build a function out of it. Thanks a lot!

Also, since i've opened this thread, can somebody tell me what *somestring means?

Like both of you did in your functions, you used an asterisk before the string variable, what does that mean?

I know & is reference, but I haven't come across this yet.

Anybody?

That is the way you reference the data pointed to by a pointer.

___________________

Sykil | | UT or die

well, my functions would of worked if name was a char array:
char name[32];
or
char name[] = "billybob";
you could also do:
char *name;
name = (char *)calloc(32, sizeof(char));
sprintf(name, "billybob");
string is just a wrapper for char arrays but does all the resizing for you. you could of probably passed it in as (char *)name by casting it.

___________________

--Life would make more sense if I had the source code--

int *i; pointer to an int
char *c; pointer to a char.

pointers are just how they sound. They point to the very first byte allocated for a variable/object/etc in memory. If you were to print out &c or &i it would print out that address in memory. *i or *c just says, use the values that i'm pointing at in memory.

___________________

--Life would make more sense if I had the source code--