Neverside

parse error

hi i dont know whats wrong with my code, im a n00b. pls help me out.

PHP:

<?php

$numberoftimings=6;
                
            
                for($i=1; $i<=$numberoftimings; $i++) {    
                    function name(i) {//LINE 121
                        switch(i) {
                            case 1: return 'fajr'; break;
                            case 2: return 'sunrise'; break;
                            case 3: return 'dhuhr'; break;
                            case 4: return 'asr'; break;
                            case 5: return 'maghrib'; break;
                            case 6: return 'isha'; break;
                        }
                    }
                    $path(i)=('namaz/time_data/' . $country1 . '/' . $city1 . '/' . $monthf . '/' . $dayf . '/' . name(i) . '.txt');
                    if(file_exists($path(i)) {
                        $data_t(i)=file_get_contents($path(i));
                    }
                    else {
                        $data_t(i)=('<span class="style111">ERROR</span><br><img src="error_small.jpg">');
                    }
                }
                
                Print($data_t(1));

?>

i get this error on IIS:

Parse error: parse error, expecting `')'' in C:\Maktab-e-Rasool\V2\ttable.php on line 121

Maybe this helps:

PHP:

<?php

$numberoftimings=6;

for($i=1; $i<=$numberoftimings; $i++){    
    
    $path[$i]=('namaz/time_data/' . $country1 . '/' . $city1 . '/' . $monthf . '/' . $dayf . '/' . name($i) . '.txt');
    if(file_exists($path[$i])){
        $data_t[$i]=file_get_contents($path[$i]);
    }else{
        $data_t[$i]=('<span class="style111">ERROR</span><br><img src="error_small.jpg">');
    }
}

function name($i) {
    switch($i){
        case 1: return 'fajr'; break;
        case 2: return 'sunrise'; break;
        case 3: return 'dhuhr'; break;
        case 4: return 'asr'; break;
        case 5: return 'maghrib'; break;
        case 6: return 'isha'; break;
    }
}
                
Print($data_t);

?>

Last edited by Hoagster, October 9th, 2005 01:45 AM (Edited 1 times)

just an explaation of what went wrong.

In PHP calling on array elements uses brakets [] not parenthesis ()

___________________

Neverside Development Director
PHP Snippets
BigToach.com - IT WORKS, TOACHY!

To add to BigToach's reply, you also left out $ infront of your variable i in this case, and it also isn't a good idea to define a function inside a loop.

thanks guys

i used that code, and the Print command doesnt print $data_t, it prints the word "ARRAY"
is this because i have not defined the $data_t variable as an array? if so, how do i do that?

i defined the variables as follows

PHP:

<?php

                $path=array(6);
                $data_t=array(6);

?>

and changed the print line to:

PHP:

<?php

                    Print($data_t=array($i));

?>

however it returns the word "ARRAY" and not the value of name function, as it should to.

It's because $data_t is an array.

you could use

PHP:

<?php
print_r($data_t);
?>

to see what is in the array.

But you could also define $data_t as an array in the beginning and print it with an foreach-loop at the end.

PHP:

<?php

$numberoftimings=6;

$path_t = array();

for($i=1; $i<=$numberoftimings; $i++){    
   //....
}

function name($i) {
    //...
}
                
foreach ($path_t as $value){
    echo $value;
}

?>

Last edited by Hoagster, October 9th, 2005 02:34 PM (Edited 2 times)

where does $value come from? or doe sit start there. what is it equal to?

$value is equal to the content of the array while the foreach function loops through it.

for reference: http://www.php.net/manual/en/control-structures.foreach.php

Last edited by Hoagster, October 9th, 2005 02:57 PM (Edited 2 times)