April 24th, 2003
10:23 PM
can someone tell me if my code is wrong in some place
well here is my code so far, have i gone wrong somwhere, since you know what im trying to achieve
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<style type="text/css">
body{ background-image: url("myimage.gif"); no-repeat; background-position: top center; }
</style>
<style type="text/css">
body{ background-image: url("myimage.gif"); background-repeat: repeat-y; }
</style>
<style type="text/css">
body{ background-image: url("myimage.gif"); no-repeat; background-position: bottom center; }
</style>
</head>
<body>
</body>
</html>
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Dunce in the corner.
April 25th, 2003
01:03 AM
Neversidian
Status: Offline!
Mix all of those body {} CSS tags into one. No need for more than one, the previous just gets overridden.
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Mugging Scotty Good.
www.muggingscotty.com
April 26th, 2003
05:19 PM
Neverside Newbie
Status: Offline!
Actually if your positioning three different images on your page(not sure if this is your goal because of same image name and different background positions)
You should insert them into their own div's:
body {font : normal 12px tahoma, Arial, Helvetica, sans-serif; color: #000; background-color: #069; padding : 0px 0px 0px 0px; }
#imgone{visibility : visible; position : absolute; z-index : 1; top : 50px; left : 50px; width : 100px; height : 100px; background-image : url(img/imgone.png); background-repeat : no-repeat;}
#imgtwo{visibility : visible; position : absolute; z-index : 1; top : 200px; left : 200px; width : 100px; height : 100px; background-image : url(img/imgtwo.png); background-repeat : no-repeat;}
#imgthree{visibility : visible; position : absolute; z-index : 1; top : 350px; left : 350px; width : 100px; height : 100px; background-image : url(img/imgthree.png); background-repeat : no-repeat;}
Hope that helps.
William
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April 29th, 2003
03:05 AM
thanks yea that does william
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Dunce in the corner.
